Shameless Self-Promotion Dept.
My approach to that last problem:
4 x 90 = 360. 5 x 92 = 460. For an average of 92, the student must score 100 on the fifth test (that is, 460 - 360).
I suspect I could turn that in to an algebraic equation, but I'm too rusty and too lazy!
My approach to that last problem:
4 x 90 = 360. 5 x 92 = 460. For an average of 92, the student must score 100 on the fifth test (that is, 460 - 360).
I suspect I could turn that in to an algebraic equation, but I'm too rusty and too lazy!